对于s[i] == 1时候，dp[i][0] = min{dp[i-(1<<j)][j]}，j不是0时为dp[i][j] = min{dp[i-(1<<j - 1)][j-1]}。对于s[i] == 0时候，dp[i][0] = min{dp[i-(1<<j)][j] + 1}，j不是0时为dp[i][j] = min{dp[i-(1<<j - 1)][j-1] + 1}。