第二题、一个公式解决
#include <iostream>

using namespace std;

typedef long long ll;

ll qiyi_num(const ll n) {
    if (n < 100) return n / 11;

    return (n/100 - 1) * 10 + ((n%100) / 11 + 1) + 9;
}

int main()
{
    ll l, r;
    while (cin >> l >> r) {
        cout << qiyi_num(r) - qiyi_num(l-1) << endl;
    }

    return 0;
}